Determine the compressive strength of a wood in Mpa. Numerical problems on strength of material.

 Question:

1. A 4”x8” wood was tested for its compressive strength parallel to the grain. The max load at failure is 12,000kgf. Determine the compressive strength in MPA.

Solution : 

The compressive strength of wood parallel to grain is obtained by pressing the wood specimen parallel to grain and load is applied till it breaks. 

Here, we need to convert the units of the load and area so that we can get the compressive strength in the desired unit. 

We know that, 

1 kgf = 9.807 N

Hence, 12000 kgf=12000* 9.807=117684 N

Again, width and thickness is given, 

Width, b= 4 inches

Thickness, t = 8 inches 

We need to convert inches to millimetres. 

1 inch = 25.4 mm

Hence, b = 4*25.4 = 101.6 mm

t = 8*25.4 = 203.2 mm

Now, area of cross section = 101.6 * 203.2 = 20645.12 mm^2

Now, Compressive strength = load / cross section area

Hence, Compressive strength = 117684 / 20645.12 = 5.70 N/mm^2 or 5.70 MPA.

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